In this section, there are 5 questions about Odd-Even Numbers. If you find it difficult to solve the questions; easy-to-understand detailed solutions can be found with the “Click for Solution” option. Good work.
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ODD EVEN NUMBERS global.matematikkolay.net 1) 0 3 2 2 2 5 2 3 3 6 5 5 5 A) 2 4 B) 13 15 2 Which 3 C) 2 7 4 a n i o f e t ? e of h o D ll wing s n eve num ) 7 4 5 E) 6 r 7 b Solution: 0 3 0 3 A) 2 4 2 e . Let ‘s examine the options one by one. The zeroth power of any number is 1 Therefore, it is odd. All positive powers of even n umbers a re 4 0 3 2 2 2 ven The number in option A is odd All natural . 2 4 O E O . B) 13 15 23 number powers of odd numbers are odd. 5 2 3 3 6 5 O O -O O . C) 2 7 4 E -O – E O The number in opt ion B is o . i dd The num – ber in opt on C is od D) 7 4 5 O E O E d 5 5 o . E) 6 7 E O O The number in option B is even The number in o ption C is odd C . rrect Answer : D 0 3 0 3 Şıkları tek tek inceleyelim; A) 2 4 2 Tüm sayıların 0’ncı kuvveti 1’dir. Dolayısıyla tektir. 4 Çift sayıların tüm pozitif kuvvetleri 0 3 2 2 2 çifttir. 2 4 T Ç T A şıkkı tektir. B) 13 15 23 Tek sayıların tüm doğal sayı kuvvetleri tektir. 5 2 3 3 6 5 5 5 2 T T – T T B şıkkı tektir. C) 2 7 4 Ç – T -Ç T C şıkkı tektir. D) 7 4 5 T -Ç T Ç D şıkkı çifttir. E) 6 7 13 Ç T T E şıkkı tektir. Doğru Cevap : D şıkkı 2) 2 5 5 Assuming a is an integer and that 7a 4 is an even number, which of the following is A) a 4 B) 5a 2 C) a a o ) an d a d nu 2 mber? D E) a 4a 3 Solution: 7a 4 E 7a E E 7a E a is even. A) a 4 E E E B) 5a 2 O.E E E E E Since the expression 7a 4 is even, we can deduce inf ormation about the value of a. Let’s examine the options one by one. 2 2 5 5 5 5 E C) a a E E E E E D) a 2 E E E E E E) a 4a 3 E E.E O E E O O Correct Answer : ODD EVEN NUMBERS global.matematikkolay.net 3) c a Considering that a, b, c, m, and n are all positive integers and that which of the following is definitely true? A If a is an even number, then c is an even number. B (a b) 2m 3 ve (b.c) 2n ) ) If b is an even number, then c is an odd number. C b is an even number. D a is an odd number. E If a is an odd number, then c is an odd number. ) ) ) Solution: c a c n (a b) O and (b.c) E (a b) O a b T g O r (O he number “2m 3″ is a sin le numbe , and ” O) 2n” is an even numbe r. Therefore, One of the numbers a and b must a n be even, and the other must be odd At least one of the numbers b and c must be even. In this case, If a is even, then b is odd, and . (b.c) E b.c E (E E) c is even. If a is odd, then b is even, and c can be either odd or even Only option A specifies a condition that meets these criteria; the other options do not provide definitive condition Correct Answer : A . 4) 2 a, b, and c are all integers, and Which of the following is definitely a 11.b.c n 12 A) ac b B) a 2b C) a b a ev en ) n um c ber D 2 b E) a b c ? Solution: In the equation , when we move 12 to the other side Since 12 is even, a must be an even number. We don’ t have a definite piece of inf ormation about b and c. Let ‘s examine the opt a 11.b.c 12 a 12.11.b.c 2 2 ions : There is no certaint y It is definitely even. There is no certaint y There is no certaint y There is no cer A) ac b E.b b E b B) a 2b E E.b E E E C) a b E b E b D) 2c b E.c b E b E) a b c E b c Correct Answer : B taint y 5) Given that a, b, and c are even numbers, which of the following is always an even a b c a b c a b A) B) C) c 2 2 2 a.b.c b c n D umbe ) E) a 2 2 r? ODD EVEN NUMBERS global.matematikkolay.net Solution: r Since a, b, and c are even numbers, we can express them as follows : a 2x, b 2y, c 2z Now, let’s examine a b c 2x 2y 2 z 2(x y z) A) x y z 2 2 2 the o p tio Th s e n : e is no certaint y a b c 2x 2y 2z 2(x y z) B) x y z 2 2 2 There is no certaint y a b 2x 2y 2(x y) C) c 2z 2z x y E 2 2 2 There is no certaint y a.b.c 2x.2y.2z D) 4x.y.z E 2 2 It is definitely even. b c 2y 2z 2(y z) E) a 2x E E y – z 2 2 2 t s T r a n C h o r r r ec e e i no n ce t i y t A swer : D ANSWER KEY 1 D 2 E 3:00 AM 4 B 5 D